# How much force can a hydraulic cylinder generate?

How much force can a hydraulic cylinder generate?

It's a basic hydraulics question, but it's a common one, so we go to our friends at Enerpac for the answer!
The following infographic shows how hydraulic forces are calculated, based on the equipment provided by Enerpac themselves.

## Force

The amount of force a hydraulic cylinder can generate is equal to the hydraulic pressure times the “effective area” of the cylinder (see cylinder selection charts). Example 1An RC-106 cylinder with 14,5 cm2 effective area operating at 700 bar will generate what force?

Force = 7000 N/cm2 x 14,5 cm2 = 101500 N = 101,5 kN

Example 2
An RC-106 cylinder lifting 7000 kg will require what pressure?
Pressure = 7000 x 9,8 N ÷ 14,5 cm2 = 4731,0 N/cm2 = 473 bar.

Example 3
An RC-256 cylinder is required to produce a force of 190.000 N. What pressure is required?
Pressure = 190.000 N ÷ 33,2 cm2 = 5722,9 N/cm2 = 572 bar.

Example 4
Four RC-308 cylinders are required to produce a force of 800.000 N. What pressure is required?
Pressure = 800.000 N ÷ (4 x 42,1 cm2) = 4750,6 N/cm2 = 476 bar.
Remember, since four cylinders are used together, the area for one cylinder must be multiplied by the number of cylinders used.

Example 5
A CLL-2506 cylinder is going to be used with a power source that is capable of 500 bar. What is the theoretical force available from that cylinder?
Force = 5000 N/cm2 x 366,4 cm2 = 1.832.000 N = 1832 kN

## Cylinder Oil Capacity

The volume of oil required for a cylinder (cylinder oil capacity) is equal to the effective area of the cylinder times the stroke*. * Note: these are theoretical examples and do not take into account the compressibility of oil under high pressure. Example 1
An RC-158 cylinder with 20,3 cm2 effective area and 200 mm stroke requires what volume of oil?
Oil Capacity = 20,3 cm2 x 20 cm = 406 cm3Example 2:
An RC-5013 cylinder has an effective area of 71,2 cm2 and a stroke of 320 mm. How much oil will be required?
Oil Capacity = 71,2 cm2 x 32 cm = 2278,4 cm3Example 3:
An RC-10010 cylinder has an effective area of 133,3 cm2 and a stroke of 260 mm. How much oil will it require?
Oil Capacity = 133,3 cm2 x 26 cm = 3466 cm3Example 4:
Four RC-308 cylinders are being used, each with an effective area of 42,1 cm2 and a stroke of 209 mm. How much oil will be required?
Oil Capacity = 42,1 cm2 x 20,9 cm = 880 cm3 for one cylinder. Multiply by four to obtain the required capacity: 3520 cm3